Question

A boy weighing 600N sits on the see-saw at a distance of 1.5 m force the pivot. What is the force F required at the other (2m away) to balance the see-saw?​

Answer 1

Answer:

to balance the sea saw the force exerted by the boy sitting 1.5 m away from the the pivot of the sea saw should be equal to the force exerted by the boy sitting 2m away from the pivot

let force of the boy sitting 2m away be x

therefore,

2*x = 1.5*600

solve this and u get the ans which is 450N

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