A boy weighs 50 n.the area of contact his two feet is 10square m.find the pressure exerted on one foot
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21
force/weight due to gravity=50 N contact area of one foot=10/2 m square
hence, pressure exerted on one foot=50/5 pa=10 pa
Answered by
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F = 50N
Area of contact of two feet = 10 cm sq.
Area of contact of 1 foot = 10/2 = 5cm sq. = 5/10000 m sq.= 0.0005 m sq.
Pressure = F/A = 50/0.0005 pa
=100000 pa
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