Question

A boy whirls a stone in a horizontal circle 1.8 m above the ground by means of a string with radius 1.2 metre while whirling stone string was horizontal it's break and stone files of her gently striking the ground 9.1 m away centripetal acceleration during the circular motion was nearly

Answer 1

we are given ...............    r= 1.2m

                     we need to find out centripetal acceleration a=v^2/r......(1)

for calculating v:

S = ut + gt^2/2                   (u = 0)

S =  gt^2/2

by putting S= 1.8m   g=10    ..........we can calculate t....

 t comes out to be o.6 s

now we know,

velocity = distance / time

v =  9.1/0.6

  =  15.1 m/s

 from (1)

a =  15.1*15.1/1.2

  = 228/1.2

  = 190       (approx)

so centripetal acceleration , a = 190 m/s^2

i hope u get that right

Answer 2

Answer:

° 188 m/s²

Explanation:

° Credits : Google