Question

a boy whose mass 50kg climbs, with constant speed, a vertical rope 6m long in 10s. boy power output during the climbs is .​

Answer 1

Answer:

P.E=m×g×h

Given m = 50 Kg , h = 10 m.

P.E=50×10×9.8

P.E=50×98=4900J

Hence increase in potential energy is 4900J.