a boy whose mass is 50 kg stands on a spring balance inside a lift the lift starts to ascend with an acceleration of 2 m/s then reading of spring balance will be
Answers
If the person is on the lift and the lift ascends with an acceleration , an additional force is acted on the downwards direction in addition to the force of gravity on person .
This additional force is equal to (m * a)
where, m = mass of boy
a = acceleration of lift
g = acceleration due to gravity = 9.8 m/s^2
So, total force acting downwards on spring balance = mg + ma
= m(g + a)
= 50 * (9.8 + 2)
= 590 N
Thus, reading of spring balance = total force/g
= 590/9.8
= 60.2041 kg
Answer:
m = mass of boy
a = acceleration of lift
g = acceleration due to gravity = 9.8 m/s^2
=> total force acting downwards on spring balance = mg + ma
= m(g + a)
= 50(9.8 + 2)
= 590 N
Therefore the reading of the spring balance = total force / g
= 590 / 9.8
= 60.2041 kg
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