Question

a boys age is one fourth that of his father after 24 years the boy will be half the age of his father find their present age​

Answer 1

Step-by-step explanation:

let father's age be x

by given condition

son's age=x/4

after 24 years

father's age=x+24

son's age=x/4 + 24

according to the statement

x/4+24=1/2*(x+24)

(x+96)/4=(x+24)/2

multiply both sides by 4

x+96=2*(x+24)

x+96=2x+48

2x-x=96-48

x=48 yrs

x/4= 48/4=12 yrs

thus father is 48 yrs old and son is 12 yrs old