Question

A boys age is one fourth that of his father. after24year the boy will be half the age of his father. find their present ages

Answer 1

boy age at present =x/4
present age of father=x
by the given data
x/4 +24=x+24/2
[96+x /4]2 =x+24
96+x =2(x+24)
96-48= 2x-x
x=48

present age of father is x=48 years
present age of son is x/4=48/4=12 years

Answer 2

Answer:

Step-by-step explanation:

boy age at present =x/4

present age of father=x

by the given data

x/4 +24=x+24/2

[96+x /4]2 =x+24

96+x =2(x+24)

96-48= 2x-x

x=48

present age of father is x=48 years

present age of son is x/4=48/4=12 y

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