Physics, asked by mdtahirahmadkhan2004, 11 months ago

a boys has a velocity of 5m/s and a uniform acceleration of 4 m/s .find distance travelled in 11th second of its position​

Answers

Answered by nishmadhawan27
0

Answer:

Explanation:

This is the answer of your question you can use it its correct

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Answered by azizalasha
1

Answer:

47 m.

Explanation:

S = 5t + 2t²

S , 11th sec. = 5(11-10) + 2(11²-10²) = 5 + 42 = 47 m.

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