a boys pulling a cart by applying a constant force of 8 N on a straight path of 20 m. On a round about of 10 m diameter , if he forgets the path and takes 1 1/2 ( one and half) turns and then continues on the straight path for another 20 m. find the net work done by the boy on the cart.
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The net work done by the boy on the cart is 60 m
Sanghamitra25:
how???
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Work Done in covering 20 m when constant force of 8N is applied
we know
W = F x s
=> W1 = 8 x 20 = 160 J
Now distance covered in one and half circle (diameter = 10m)
radius = 5 m
Distance covered in one circle
= 2 πr = 2 x 3.14 x 5 = 31.4 m
Distance covered in half circle
= πr = 3.14 x 5
= 15.7
distance covered in one and a half circle
= 15.7 + 31.4 = 47.1 m
Now ,
Workdone will be
W2 = 8 x 47.1 = 376.8 J
Travelling again for 20 m
W3 = 20 x 8 = 160 J
Total work done
W1 + W2 + W3
160 + 376.8 + 160
= 696.8 ≈ 697 Joules
we know
W = F x s
=> W1 = 8 x 20 = 160 J
Now distance covered in one and half circle (diameter = 10m)
radius = 5 m
Distance covered in one circle
= 2 πr = 2 x 3.14 x 5 = 31.4 m
Distance covered in half circle
= πr = 3.14 x 5
= 15.7
distance covered in one and a half circle
= 15.7 + 31.4 = 47.1 m
Now ,
Workdone will be
W2 = 8 x 47.1 = 376.8 J
Travelling again for 20 m
W3 = 20 x 8 = 160 J
Total work done
W1 + W2 + W3
160 + 376.8 + 160
= 696.8 ≈ 697 Joules
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