A brake applied to a train moving at 90 km/hr produces the retardation of 5m/s².What distance will it cover before coming to a stop.
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Answer:
The train will cover 62.5m before it comes to a stop
Explanation:
Using the equation v^2 = u^2 + 2as
we can say u(initial velocity) = 90kmph = 25 m/s
and final velocity v is 0 since the train comes to a stop
Acceleration = -5m/s (retardation)
Plugging the values in, we get
0^2 = 25^2 + 2(-5)(s)
-25 x 25 = -10s
s = 625/10= 62.5 m
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