Question

A brake applied to a train moving at 90 km/hr produces the retardation of 5m/s².What distance will it cover before coming to a stop.​

Answer 1

Answer:

The train will cover 62.5m before it comes to a stop

Explanation:

Using the equation v^2 = u^2 + 2as

we can say u(initial velocity) = 90kmph = 25 m/s

and final velocity v is 0 since the train comes to a stop

Acceleration = -5m/s (retardation)

Plugging the values in, we get

0^2 = 25^2 + 2(-5)(s)

-25 x 25 = -10s

s = 625/10= 62.5 m