Question

A brass bar of length 2m area of cross section 0.01m^2 is clamped horizontally and a depression of 32mm is found for a load of 10kg.calculate Young's modulus of material of bar

Answer 1

Answer:

$y = \frac{f \times l}{area \times change \: in \: length} \\ y = \frac{100 \times 2}{ {10}^{ - 2} \times 32 \times {10}^{ - 3} } =16 \times {10}^{5}$

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