Question

A brass of length 2 m and cross-sectional area 2.0 cm^(2) is attached end to end to a steel rod of length and cross-sectional area 1.0 cm^(2). The compound rod is subjected to equal and oppsite pulls of magnitude 5 xx 10^(4) N at its ends. If the elongations of the two rods are equal, the length of the steel rod (L) is {Y_(Brass) = 1.0 xx 10^(11) N//m^(2) and Y_(steel) = 2.0 xx 10^(11) N//m^(2)

Answer 1

Answer:

Lsteel=2meter

Explanation:

Y=FL/ΔlA   Acc.to quez ΔLsteel=ΔLbrass so,Fsteel×Lsteel/Ysteel×Asteel=Fbrass×Lbrass/Ybrass×Abrass