Question

A brass piece of 200 g at 100°C is dropped into 500 ml of water at 20°C. The final temperature is 23°C. Calculate the specific heat of brass

Answer 1

The specific heat of the brass will be 409 j/kgC

Explanation:  

Mass of brass = = 200g = 0.2 kg

Temperature of mb brass = Tb = 100 C

Initial Temperature = T1 = 20 degree Celsius

Final Temperature = T2 = 23 degree Celsius

Mass of water = mw = 500ml = 0.5kg

We know that:

C = mwCw (T2 – T1)/ mb(Tb -T2)

By putting values in above equation, we get,

C = 409 j/kg degree Celsius