A brass piece of 200 g at 100°C is dropped into 500 ml of water at 20°C. The final temperature is 23°C. Calculate the specific heat of brass
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The specific heat of the brass will be 409 j/kgC
Explanation:
Mass of brass = = 200g = 0.2 kg
Temperature of mb brass = Tb = 100 C
Initial Temperature = T1 = 20 degree Celsius
Final Temperature = T2 = 23 degree Celsius
Mass of water = mw = 500ml = 0.5kg
We know that:
C = mwCw (T2 – T1)/ mb(Tb -T2)
By putting values in above equation, we get,
C = 409 j/kg degree Celsius
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