Question

a brass rod is 2 m long at a certain temperature. what is it's length for a temperature rise of 100 k, if the expansivity of mercury ?.​

Answer 1

Answer:

Explanation:

t is known that, distance between the two points is obtained by subtracting the smaller co-ordinate from larger co-ordinate.

(i) The co-ordinates of points B and E are 2 and 5 respectively. We know that 5 > 2.

∴ d(B, E) = 5 − 2 = 3

(ii) The co-ordinates of points J and A are −2 and 1 respectively. We know that 1 > −2.

∴ d(J, A) = 1 − (−2) = 1 + 2 = 3

(iii) The co-ordinates of points P and C are −4 and 3 respectively. We know that 3 > −4.

∴ d(P, C) = 3 − (−4) = 3 + 4 = 7

(iv) The co-ordinates of points J and H are −2 and −1 respectively. We know that −1 > −2.

∴ d(J, H) = −1 − (−2) = −1 + 2 = 1

(v) The co-ordinates of points K and O are −3 and 0 respectively. We know that 0 > −3.

∴ d(K, O) = 0 − (−3) = 0 + 3 = 3

(vi) The co-ordinates of points O and E are 0 and 5 respectively. We know that 5 > 0.

∴ d(O, E) = 5 − 0 = 5

(vii) The co-ordinates of points P and J are −4 and −2 respectively. We know that −2 > −4.

∴ d(P, J) = −2 − (−4) = −2 + 4 = 2

(viii) The co-ordinates of points Q and B are −5 and 2 respectively. We know that 2 > −5.

∴ d(Q, B) = 2 − (−5) = 2 + 5 = 7