Question

a brass sphere of mass 0.4kg at 100 degree Celsius is dropped into 1kg of water at 20degree Celsius the final temperature of the mixture is 23degree Celsius. find the S.H.C of brass
​

Answer 1

Here, mass of brass, m

1

=0.4kg

Temperature of brass, T

1

=100

o

C

Mass of water, m

2

=1kg

Temperature of water, T

2

=20

o

C

Final temperature, T=23

o

C

Specific heat of brass, C

1

=?

Specific heat of water,

C

2

=4180Jkg

−1

o

C

−1

From relation, Heat lost = Heat gained

m

1

C

1

(T

1

−T)=m

2

C

2

(T−T

2

)

Putting values we get,

0.4×C

1

×(100−23)=1×4180×(23−20)

⇒C

1

=

0.4×77

1×4180×3

=407Jkg

−1

o

C

−1

Specific heat of brass =407Jkg

−1

o

C

−1

Answer 2

Answer:

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