Question

A brass wire of diameter 1mm and of length 2m is stretched by applying a force of 20N .If the increase in length is 0.51mm Then the Young's modulus of the wire is

please do this question​

Answer 1

Explanation:

گھنےجنگلوں میں وہ تنہا گھومتی تھی٠٠

خدا جانے وہ کس کو ڈھونڈھتی تھی۔۔۔

Answer 2

Answer:

• $9.984\times10^{10}Nm^{-2}$

Explanation:

Given

• l = 2m
• F = 20 N
• D = 1 mm
• $r = \frac{1}{2}m\:m = \frac{1}{2}\times 10^{-3}m$
• e = 0.51 mm = 51×10$^{-5}$m
• A = πr² = $\frac{22}{7}\times\frac{1}{4}\times10^{-6}m^{2}$

$\implies\:\:y=\frac{Fl}{Ae}$

$\implies\:\:y= \frac{20\times2}{ \frac{22}{7}\times\frac{1}{4}\times10^{-6}\times51\times10^{-5}}$

$\implies\:\:y= 0.09984\times10^{12}$

$\implies\:\:y= 9.984\times10^{10}Nm^{-2}$