Question

a) Breifly explain Bohr-Bury scheme for the distribution of electrons in different shells.



b) An atom has 2 electrons in its outermost shell M. What is the atomic number of

the element ? Also mention its name.

anybody plz help me today is our science exam it's very urgent plz help me ​

Answer 1

Answer:

1)

2 nsquare rule

first shell=2*1 square=2

second shell=2*2square=8

2)

12…4

magnesium

Answer 2

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a) The distribution of electrons in different orbits or shells is governed by a scheme known as Bohr bury scheme.The arrangement of electrons in various energy levels of an atom is known as the electronic configuration of the atom.

According to this scheme :-

1. The electrons are arranged around the nucleus in different energy levels or energy shells. The electrons first occupy the shell with the lowest energy i.e., closest to the nucleus.
2. The first or the innermost energy shell (K or n = 1) can take only two electrons.
3. The second shell (L or n = 2) can contain upto 8 electrons.
4. From third shell (M or n = 3) onwards, the shells become bigger. The third shell can accommodate as many as 18 electrons. In general, the maximum number of electrons that can be present in any shell is 2n2 where n is the number of energy shell. Thus, the first orbit (n = 1, known as K shell) can contain 2 × 12 = 2 electrons, the second orbit (n = 2, known as L shell) can contain 2 × 22 = 8 electrons.

b) Since the element has 2 electrons in it s M shell, it’s

• Atomic no : 12
• Electronic configuration : 2,8,2
• Number of protons : 12
• Valency : 2
• Name of the element : Magnesium

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