Question

a brick having weight 30 newton is 21 cm long 10 cm wide and 6 m high. the face of the brick on the ground having dimensions 21 cm and 6 cm is in contact with the ground find the pressure exerted on the ground by the face of brick
write the explaination....​

Answer 1

Answer:

Pressure =2830 N

Explanation:

Given that :weight = 30 N

Area of space on which pressure is exerted =21cm×6cm

=106 /100×100 m^2

=. 0106 m^2

Solution :

As we know that

$pressure \: = \frac{normal \: force }{area}$

Here the weight of body will be act as the normal force because weight act in the normal direction.

$pressure = \frac{30}{.0106} \\ = 2830 \frac{n}{ {m}^{2} }$

Answer 2

Explanation:

pressure = force/area = 30 N / (21×6)×10-4 m2 = 2381 N/m2