Question

A brick is 16 cm long 5 cm wide and 5 cm thick. It weighs 8 newton and is lying on the ground. Find the pressure exerted by the brick on the ground.

Answer 1

Answer :-

The brick exerts a pressure of 1000 Pascal on the ground .

Explanation :-

We have :-

→ Length of the brick = 16 cm

→ Width of the brick = 5 cm

→ Thickness = 5 cm

→ Weight (Force) = 8 N

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Firstly, let's calculate the contact area of the brick

⇒ Area = Length × Breadth

⇒ Area = (16 × 5) cm²

⇒ Area = 80 cm²

Now, let's convert the unit of area from cm² to m² .

⇒ 1 cm² = 0.0001 m²

⇒ 80 cm² = 80(0.0001)

⇒ 0.008 m²

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Finally, pressure exerted by the brick on the ground will be :-

Pressure = Force/Contact Area

⇒ Pressure = Weight/Contact Area

⇒ Pressure = 8/0.008

⇒ Pressure = 8000/8

⇒ Pressure = 1000 Pa

Answer 2

Answer:

Given :-

• A brick is 16 cm long 5 cm wide and 5 cm thick.
• It weight is 8 Newton and is lying on the ground.

To Find :-

• What is the pressure exerted by the brick on the ground.

Formula Used :-

$\clubsuit$ Area Of Rectangle Formula :

$\mapsto \sf\boxed{\bold{\pink{Area_{(Rectangle)} =\: Length \times Breadth}}}$

$\clubsuit$ Pressure Formula :

$\mapsto \sf\boxed{\bold{\pink{Pressure =\: \dfrac{Force}{Area}}}}$

Solution :-

First, we have to find the area of bricks :

Given :

• Length = 16 cm
• Breadth = 5 cm

According to the question by using the formula we get,

$\implies \bf Area_{(Brick)} =\: Length \times Breadth$

$\implies \sf Area_{(Brick)} =\: 16 \times 5$

$\implies \sf\bold{\purple{Area_{(Brick)} =\: 80\: cm^2}}$

Now, we have to convert the area cm² into m² :

$\implies \sf Area =\: 80\: cm^2$

$\implies \sf Area =\: \dfrac{8\cancel{0}}{1000\cancel{0}}\: m^2\: \: \: \bigg\lgroup \sf\bold{\pink{1\: cm^2 =\: \dfrac{1}{10000}\: m^2}}\bigg\rgroup$

$\implies \sf Area =\: \dfrac{8}{1000}\: m^2$

$\implies \sf\bold{\green{Area =\: 0.008\: m^2}}$

Now, we have to find the pressure exerted by the brick on the ground :

Given :

• Weight or Force = 8 N
• Area = 0.008 m²

According to the question by using the formula we get,

$\longrightarrow \sf Pressure =\: \dfrac{8}{0.008}$

$\longrightarrow \sf Pressure =\: \dfrac{8}{\dfrac{8}{1000}}$

$\longrightarrow \sf Pressure =\: \dfrac{8}{1} \times \dfrac{1000}{8}$

$\longrightarrow \sf Pressure =\: \dfrac{\cancel{8000}}{\cancel{8}}$

$\longrightarrow \sf Pressure =\: \dfrac{1000}{1}$

$\longrightarrow \sf\bold{\red{Pressure =\: 1000\: Pascal}}$

${\footnotesize{\bold{\underline{\therefore\: The\: pressure\: exerted\: by\: the\: brick\: on\: the\: ground\: is\: 1000\: Pascal\: .}}}}$