A brick is 32cm long 10cm wide and 10cm thick. it weighs 16 N and is lying on the ground. find the pressure exerted by the brick on the ground.
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The brick can either be placed lengthwise, breadthwise or heightwise
In all these cases, the area of contact changes which changes the pressure
The three areas of contact are,
length×breadth = 320cm² = 320×10^-4 m²
breadth×height = 100cm² = 100×10^-4 m²
length×height = 320cm² = 320×10^-4 m²
Hence,
Pressure = Force/Area
P1 = 16/320×10^-4 = 160000/320 = 500 Pa
P2 = 16/100×10^-4 = 1600 Pa
P3 = 16/320×10^-4 = 160000/320 = 500 Pa
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