Question

A brick of dimensions 15cm*10cm*5cm applies a force of 1.5 when placed on a surface. Find out the pressure it exerts when it is placed in vertical and horizontal positions

Answer 1

Answer:

lLet P1,P2 and P3 be the pressures exerted by the brick while resting on different faces.

The dimensions of the given brick are 20cm×10cm×5cm

Case (i) : When the block is resting on 20cm×10cmface.

Thrust acting= Weight of the brick

T=500gwt

Area of constant (A)=20cm×10cm

Pressure exerted (P1)

=AreaThrust=20×10500

∴P1=2.5gwtcm−2

Case (ii) : When the block is resting on 20cm×5cmface

Thrust= Weight of the brick

=500gwt

Area of constant (A)=20cm×5cm

Pressure exerted

(P2)=AreaThrust=20×5500

∴P2=5gwtcm−2

Case (iii) : When the block on 10cm×5cmface

Thrust= Weight of the brick =500g.wt.

Area of contact =10cm×5cm

Pressure=

Answer 2

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Let P1,P2 and P3 be the pressures exerted by the brick while resting on different faces.

The dimensions of the given brick are 20cm×10cm×5cm

Case (i) : When the block is resting on 20cm×10cmface.

Thrust acting= Weight of the brick

T=500gwt

Area of constant (A)=20cm×10cm

Pressure exerted (P1)

=Area Thrust=20×10500

∴P1=2.5gwtcm−2

Case (ii) : When the block is resting on 20cm×5cmface

Thrust= Weight of the brick

=500gwt

Area of constant (A)=20cm×5cm

Pressure exerted

(P2)=Area Thrust=20×5500

∴P2=5gwtcm−2

Case (iii) : When the block on 10cm×5cmface

Thrust= Weight of the brick =500g.wt.

Area of contact =10cm×5cm