A brick of mass 1.2 kg having a dimension of 30 cm x 12 cm x 6 cm is resting on a surface with its largest area in contact. Calculate the pressure due to the brick on the surface. If the brick is now resting on its smallest area, calculate the new pressure applied by the brick on the surface.
Answers
Answer:
For Largest area = 326.67 Pa
For Smallest area = 1633.33 Pa
Step-by-step explanation:
The surface area of the brick in contact with the surface when it is resting on its largest area is:
A = l x b = 30 cm x 12 cm = 360 cm^2
The volume of the brick is:
V = l x b x h = 30 cm x 12 cm x 6 cm = 2160 cm^3
The mass of the brick is given as 1.2 kg.
We can use the formula:
Pressure = Force / Area
The weight of the brick (force) is given by:
Weight = Mass x Gravity
where gravity is approximately 9.8 m/s2
Converting the mass and gravity to their SI units:
Weight = 1.2 kg x 9.8 m/s² = 11.76 N
Therefore, the pressure due to the brick on the surface when it is resting on its largest area is:
Pressure = Weight / Area = 11.76 N / 0.036 m² = 326.67 Pa
When the brick is resting on its smallest area, the surface area in contact with the surface will be:
A = l x b = 12 cm x 6 cm = 72 cm²
Using the same weight and the new surface area, the pressure applied by the brick on the surface will be:
Pressure = Weight / Area = 11.76 N / 0.0072 m² = 1633.33 Pa
Therefore, the pressure applied by the brick on the surface when it is resting on its smallest area is 1633.33 Pa