Question

A brick of mass 1 kg and density 2500kg/m3 is completely immerged in a water of density 1000 kg/m3. The mass of water displaced by the brick is a) 1/25 b) 1/2.5kg c) 2.5 Kg d) 0.25 Kg

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Mass\:displaced=0.4\:kg}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass \: of \: brick( m_{1}) = 1 \: kg \\ \\ \tt: \implies Density \: of \: brick( \rho_{1}) = 2500 \: kg/ {m}^{3} \\ \\ \tt: \implies Density \: of \:water( \rho_{2}) = 1000 \: kg {m}^{3} \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Mass \:of \: water \: displaced( m_{2}) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Density( \rho_{1}) = \frac{Mass( m_{1})}{Volume( v_{1}) } \\ \\ \tt: \implies 2500 = \frac{1}{ v_{1} } \\ \\ \tt: \implies v_{1} = \frac{1}{2500} \: {m}^{3} - - - - - (1) \\ \\ \bold{Again , } \\ \tt: \implies Density( \rho_{2}) = \frac{Mass( m_{2})}{Volume( v_{1}) } \\ \\ \tt: \implies 1000 = \frac{ m_{2} }{ \frac{1}{2500} } \\ \\ \tt: \implies 1000 = 2500 \times m_{2} \\ \\ \tt: \implies m_{2} = \frac{1000}{2500} \\ \\ \tt: \implies m_{2} = \frac{10}{25} \\ \\ \green{\tt: \implies m_{2} =0.4 \: kg} \\ \\ \green{\tt \therefore Mass \: displaced \: is \: 0.4 \: kg}$

Answer 2

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