A brick of mass 2.5 kg is placed on a table. The brick has a dimension of 25 cm x 10 cm x 5 cm. The brick is placed on the table along the surface enclosed by its length and height. Calculate the pressure exerted by the brick on the table.
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Given:-
- Mass of Bricks (m) = 2.5kg
- Length of box (l) = 25cm
- Breadth of box (b) = 10cm
- Height of box = 5cm
To Find:-
- Pressure exerted by the brick on the table.
Solution:-
According to Give Question
The acceleration due to gravity is 9.8m/s² which is acting on the box in downward direction
The brick is placed on the table along the surface enclosed by its length and height
Force = mass× acceleration due to gravity
→ F = mg
→ F = 2.5 ×9.8
→ F = 24.5N
Area on which the force acting (According to the Question)
∴ Area = length × height
→ Area = 25×5
→ Area = 125cm²
As we know that
1m² = 100000cm²
∴ 125cm² = 125/100000 = 0.00125m²
Now
We know that
→ Pressure = Force/Area
Substitute the value we get
→ Pressure = 24.5/0.00125
→ Pressure = 19600Pa
∴The pressure acting on the box is 19600Pa.
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