Question

A brick of mass 2 kg having dimensions 40 cm x 12 cm x 6 cm is resting on a surface with its largest area in contact. Calculate the pressure due to the brick on the
surface.
[Take g= 10 ms2]​

Answer 1

Required Answer:-

The weight of the body is the force applied by the brick on the ground$.$ And, weight is given by mg.

So, Weight of the brick (force) = 2 kg × 10 m/s²

Weight = 20 kg m/s² or 20 N

Now, it is said that the brick is resting on a surface with its largest area in contact. It means, two larger sides face. Area in contact = 40 cm × 12 cm = 480 cm² or 0.048 m²

To Find:-

Pressure due to brick in the surface:

= F / A

= 20 N / 0.048 m²

= 20000/48 N/m²

= 416.67 N/m²

= 416.67 pascals (approx.)