A brick of mass 2 kg is dropped from a rest position at certain height . find the height if the brick strike the ground with a velocity of 19.6 m/s
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Answer:
19.6
initial vel=0 (since it started from rest)
final vel=19.6
acceleration=9.8
using 3rd eq of motion
2as=v^2-u^2
2x9.8xs=19.6x19.6
2s=2x19.6
s=19.6
Explanation:
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