Question

A brick of mass 2kg just begins to
slide down on inclined plane at an
angle of 45° with the horizontal. The
force of friction is​

Answer 1

Explanation:

Perimeter of trapezium = 104 m

Length of Non-parallel sides = 18 m and 22 m

Altitude = 16m

Area of Trapezium = 0.5 * (sum of parallel sides)*altitude ------ (1)

Sum of parallel sides = Perimeter - (sum of non-parallel sides) = 104 m - (18+22)m = 104-40 m = 64 m

From (1), Area of Trapezium = 0.5*64*16 = 512 m^2

Ans: Area of trapezium = 512 m^2

Answer 2

Given :-

• A brick of mass 2kg .

• It slide down an inclined plane at an angle of 45° with the horizontal.

To Find :-

• The force of friction .

Solution :-

• m of brick = 2kg

• θ = 45°

The brick slide down an inclined plane.

It means the friction is acting here opposing the motion of the brick .

• Force of friction is (f)

f = mg sinθ

We, know g = 9.81 m/s² gravitational constant of earth ≈ 9.8m/s²

➝ f = 2 × 9.8 × sin45°

➝ f = 2 × 9.8 × $\dfrac{1}{ \sqrt{2} }$

➝ f = √2 × 9.8

➝ f = 1.414 × 9.8

➝ f = 13.86 N

The force of friction is 13.86 newton .

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