a brick of weight 2 kgf and
dimensions 20 cm x 10 cm x 5 cm placed in
three different positions on the ground. Find the
pressure exerted by the brick in each case.
Answers
Answered by
11
Answer: the pressure exerted when it is placed with dimension 5 cm will be max
Explanation:
P = Mass/ area as the area in the third case is the minimum the pressure will be more the minimum pressure will be exerted when placed with dim/. 20 cm
Answered by
2
Answer:
We know that P = F/A, here A=effective area
In first case , P = mg/A = 2 × 10 = 1000 Pa
In second case , P = 2 × 10/0.05 × 0.1 = 4000 Pa
In third case , P = 2 × 10/0.05 × 0.2 = 2000 Pa
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