A brick weighing 20N and having dimensions 25x10x5cm is kept on the ground in three different ways. calculate it's pressure kept in three different ways
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As we know that pressure is Force per unit area and force is given 20N and the area of cuboid will remain same when kept in three different ways as all dimensions are given of cuboid
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Weight=20NCase 1-Area=250cm^2=0.025m^2Pressure=20/0.025=800Pa
Case 2-Area=125cm^2=0.0125m^2Pressure=20/0.0125=1600Pa
Case 3-Area=50 cm^2=0.005m^2Pressure=20/0.005=4000Pa
Case 2-Area=125cm^2=0.0125m^2Pressure=20/0.0125=1600Pa
Case 3-Area=50 cm^2=0.005m^2Pressure=20/0.005=4000Pa
maryamfatima98765432:
Can you please explain this
Please write the formula
Formula of cuboid is l×b×h and we have all the dimensions for this formula and after getting the area apply the formula of pressure i.e force ÷Area .
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