Question

A bridge is in the shape of trapezium in which the engineers designed the shape buy it follow in which parallel side are 30 metre and 60 m and height of the bridge is 30 M from the ground level. find its area

Answer 1

area of trapezium = 1/2×h×( sum of parallel sides)
= 1/2×30×(30+60)
= 15×90
= 1350m^2

Answer 2

Area of trapezium shaped bridge=

1/2(sum of parallel sides) ×h



=1/2(30+60)×30



= 1/2×90×30



$= 1350 {m}^{2}$


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