A bright object 50mm high stands on the axis of a concave mirror of focal length 100mm and at a distance of 300mm from the concave mirror. How big the image will be ?
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firstly find the v
1/f = 1/v + 1/u
1/v =1/f - 1/u
1/v = 1/100 - 1/300
1/v = 3-1 / 300
1/v = 2/300
v = 150mm
hence the is in front of mirror and in 150mm
OO'/II' = -V/U
50/II' = 150/300
50/II' = 1/2
II' = 100MM
MEANS THE SIZE OF IMAGE IS 100MM
1/f = 1/v + 1/u
1/v =1/f - 1/u
1/v = 1/100 - 1/300
1/v = 3-1 / 300
1/v = 2/300
v = 150mm
hence the is in front of mirror and in 150mm
OO'/II' = -V/U
50/II' = 150/300
50/II' = 1/2
II' = 100MM
MEANS THE SIZE OF IMAGE IS 100MM
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