A broker charges brokerage @ 0.75% from the seller and 1.5% from the buyer of a house. If he gets a brokerage of 4050, calculate how much amount of brokerage is received from the buyer as well as seller and what is the price of the house sold?
Answers
Given : A broker charges brokerage @ 0.75% from the seller and 1.5% from the buyer of a house.
he gets a brokerage of 4050,
To Find:
How much amount of brokerage is received from the buyer
How much amount of brokerage is received from the seller
what is the price of the house sold
Solution:
Let say price of the house sold = 10000P
brokerage received from the seller = (0.75/100) * 10000P = 75P
brokerage received from the buyer = (1.5/100) * 10000P = 150P
Total Brokerage received = 75P + 150P = 225P
Total Brokerage = 4050
=> 225P = 4050
=> P = 18
brokerage received from the seller = 75P = 75 * 18
= 1350
brokerage received from the buyer = 150P = 150 * 18
= 2700
price of the house sold = 10000P = 10000 * 18
= 180000
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