Question

A bronze statue weighs 4800N and it exerts a pressure of 24000Pa on the ground on which it stands.Find the area of base.​

Answer 1

Answer:

0.2 m^2

Explanation:

Force = 4800 N

Pressure = 24000 Pa

Pressure = Force / Area

24000 = 4800 / Area

Area = 4800 / 24000

Area = 0.2 m^2

Hope this helps! :)

Answer 2

Gɪᴠᴇɴ :-

• Force(F) = 4800 Newtons
• Pressure (P) = 24000 Pascal

Tᴏ ғɪɴᴅ :-

• Area (A) of base

sᴏʟᴜᴛɪᴏɴ :-

We know that,

$\implies \sf \: Pressure \: (P) = \frac{Force(F)}{Area(A)} \\ \\ \\ \implies \sf \: P = \frac{F}{A}$

Put the above given values in it, we get,

$\implies \sf \: 24000 = \frac{4800}{A} \\ \\ \\ \implies \sf \: A = \frac{4800}{24000} \\ \\ \\ \implies \sf \: A = 0.2 {m}^{2}$

Hence,

• Area of Base = 0.2m²