Question

a brooch is made with silver wire in the form of a circle with diameter 35mm. the wire also used in making 5 diameter which divide the circle into 10 equal sectors. find the total length of the silver wire required. please don't miss any step

Answer 1

Given,
Diameter = d = 35mm
Radius of the circle =r= $\frac{d}{2} = \frac{35}{2}$
Circumference of brooch = 2πr
                                        = 2*22/7*35/2
                                        = 110mm
Length of wire required = 110 + 5 x 35
                                      = 110 + 175
                                      = 285mm

Answer 2

Answer:

Given, diameter =35mm

Therefore radius =35/2mm

1) circumference of circle =2*22/7*r

=2*22/7*35/2

=110mm

Length of 5 Silver wire =5*35=175

Total length of the silver wire =110 +175

=285mm

2) theta =360/10=36

Radius =35/2

Area of each sector =theta/360*22/7*r^2

=36/360*22/7*35/2*35/2

=384mm^2

I hope this will help you

Step-by-step explanation: