Math, asked by drsagar171, 1 year ago

A brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used in making 5 diameters which divide the circle into 10 equal parts. Find the total length of the silver wire required.

Answers

Answered by subrataana9349
6

Answer:

Step-by-step explanation:

Number of diameters = 5

Length of diameter = 35 mm

∴ Radius = 35/2 mm

(i) Total length of silver wire required = Circumference of the circle + Length of 5 diameter

= 2π r + (5×35) mm = (2 × 22/7 × 35/2) + 175 mm

= 110 + 175 mm = 185 mm

(ii) Number of sectors = 10

Area of each sector = Total area/Number of sectors

Total Area = π r2 = 22/7 × (35/2)2 = 1925/2 mm2

∴ Area of each sector = (1925/2) × 1/10 = 385/4 mm2

Answered by srishti1123456
6

Answer:

285mm

Step-by-step explanation:

d = 35 cm

length of wire used = 2 pi r +(5)(35)

                                = 2 (22/7)( 35/2) +175

                                = 110 + 175

                                = 285mm

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