Question

A brother is 2 years elder to his sister. Five years ago,one-third of his age was equal to three-sevenths of her age. Find their present ages?

Answer 1

Let the sister's age be x.

Then the brother's age is x+2

five years ago:

sister's age is x-5

brother's age is x-5+2

==> x-3

1/3 rd of his age is (x-3) / 3

3/7 th of her age is 3 (x-5) / 7

Thus:

(x-3)/3=3(x-5)/7

Cross multiplying gives:-

==> 7(x-3) = 9(x-5)

==> 7x-21 = 9x-45

==> 7x-9x = -45+21

==> -2x = -24

==> x= -24/-2

==> x=12

Hence sister's age is 12 and brother's age is 12+2 which is 14

Hope it helps you.

========================================================

Answer 2

Hlo mate :-

Solution :-

________________________________________________________________________________________

Let the sister's age be x.

Then the brother's age is x+2

five years ago:

sister's age is x-5

brother's age is x-5+2

==> x-3

1/3 rd of his age is (x-3) / 3

3/7 th of her age is 3 (x-5) / 7

Thus:

(x-3)/3=3(x-5)/7

Cross multiplying gives:-

==> 7(x-3) = 9(x-5)

==> 7x-21 = 9x-45

==> 7x-9x = -45+21

==> -2x = -24

==> x= -24/-2

==> x=12

Hence sister's age is 12 and brother's age is 12+2 which is 14

________________________________________________________________________________________

☆ ☆ ☆ Hop It's helpful ☆ ☆ ☆