A bubble of air is underwater at temperature 15°C
and the pressure 1.5 bar. If the bubble rises to the
surface where the temperature is 25°C and the
pressure is 1.0 bar what will happen to the volume of
the bubble
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Explanation:
given A bubble of air is underwater at temperature 15°C
and the pressure 1.5 bar. If the bubble rises to the
surface where the temperature is 25°C and the
pressure is 1.0 bar what will happen to the volume of
the bubble ?
.We know that from ideal equation
V ∝ T/P
Given T1 = 15 + 273 = 288, P1 = 1.5 bar
T2 = 25 + 273 = 298, P2 = 1 bar
V1 ∝ 288 / 1.5
V1 ∝ 192 V2 α 298 / 1
V2 / V1 = 298 / 192 = 1.55 = 1.6 V
Volume is greater by a factor of 1.6.V
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