A bucket containing water is tied to one end of a rope 5 m long and it is rotated in a
vertical circle about the other end. Find the number of rotations per minute in order
that the water in the bucket may not spill. ( Ans: n=13.37 rpm)
Answers
Answered by
43
Answer:
Centripetal acceleration = g
w^2 x r = g (w = angular acceleration)
w^2 = g/r = 9.8/5 = 1.96
w = 1.4 rad/s
w = 1.4 x 60/2π rpm = 13.37 rpm
Answered by
0
Let r =5m
Centripetal acceleration= g;
So, g=w^2*r (w=Angular acceleration)
w^2 = g/r
w^2 = 9.8/5
w^2 =1.96
W=1.4rad/s
W=1.4*60/2π rpm = 13.37rpm
Similar questions
Math,
1 month ago
Math,
1 month ago
Science,
1 month ago
Social Sciences,
2 months ago
Environmental Sciences,
2 months ago
Hindi,
9 months ago
English,
9 months ago