Question

A bucket contains 3 red, 4 blue, 6 green, 7 yellow and 5 orange balls. Find the mentioned probabilities a. P (a red ball) = b. P (one red or one blue ball) = c. P (one green ball) = d. P (1 orange ball) = e. P (1 blue ball) = f. P (7 yellow balls) = g. P (a black ball) = h. P (6 green balls) =​

Answer 1

Step-by-step explanation:

a bucket contains total ball = 3+4+6+7+5=25

a. p of red ball =3/25

b. p of blue ball =4/25

now green =6/25

yellow=7/25

orange=5/25=1/5

Answer 2

Answer:

total balls = 25

a. P(a red ball) = 3/25 = 0.12

b. P(one red or one black ball) = 7/25 = 0.28

c. P(one green ball) = 6/25= 0.24

d. P(one orange ball) = 5/25 = 0.2

e. P(1 blue ball) = 4/25 =0.16

f. P(7 yellow ball) = 1/25 =0.04

g. P(a black ball) = 4/25 = 0.16

h. P(6 green balls) = 1/25 = 0.04