Question

A bucket contains 50 lottery balls numbered 1-50. One is drawn at random. P( at least 20| prime number

Answer 1

Answer:

Step-by-step explanation:

This is a problem of conditional probability that can be calculated by the formula:

P(B | A) = P(A ∩ B) / P(A)

We know that:

- between 1 and 50 there are 41 two-digit numbers, therefore 

P(A) = 41/50 = 0.82

- between 1 and 50 there are 8 multiples of six, therefore

P(B) = 8/50 = 0.16

- between 1 and 50 there are 7 two-digits mutiples of six, therefore

P(A ∩ B) = 7/50 = 0.14

Now, we can calculate:

P(B | A) = P(A ∩ B) / P(A)

             = 0.14 / 0.82

             = 0.17

Therefore, the probability of getting a multiple of 6 if we draw a two-digit number is 17%