Question

a bucket contains 8 kg of water at 25°c. 2 kg of water at 80 °C is poured into it. neglecting the heat energy absorbed by the bucket, calculate the final temperature of water.

Answer 1

ANSWERS :-


Let final temperature of water be t°C

fall in temperature of hot water = (80 - t) °C

Heat energy lost by hot water = 2 * C * (80 - t) ..... (I)

Rise in temperature of cold water = ( t - 25) °C

Heat energy gained by cold water = 8 * C * (t- 25 ) ...(ii)


where c is the specific heat capacity of water .

Neglecting the heat energy absorbed by the bucket ,

Heat energy lost by hot water = Heat energy lost by cold water

so,

2 * C * (80 - t ) = 8 * C * (t -25 )
or,

2(80-t) = 8(t-25)
or,
160 - 2t = 8t - 200
or,
10t = 360
or,

t = 360/ 10

= 36 °C


thus,

final temperature of water will be 36 °C

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❤BE BRAINLY ❤

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