Question

A bucket contains a mixture of two liquida a and b im tje proportion 5:3 if 16 litre of the mixtures is replaced by 16 litres of liquid


b.then the ratio of b i bucket

Answer 1

Let bucket contains 5x and 3x of liquids A and B respectively.
When 16 litres of mixture are drawn off, quantity of A in mixture left:
[5x - (5/8)*16] = (5x - 10)
Similarly quantity of B in mixture left,
[3x - (3/8)*16] = (3x - 6)
Now the ratio becomes,
(5x - 10)/(3x - 6) = 3/5
=>25x - 50 = 9x - 18
=> 16x = 32
=> x = 2.
So, quantity of liquid B initially,
= 3*2 = 6 litres.

Answer 2

Answer:

Initially the ratio is 5x/3x.

We know that 16 litres is removed from TOTAL MIXTURE, so the removal is in the same ratio. After removal of the total 16 litres, the removal will be in the ratio of 5:3, which will result is 10 ltrs from A and 6 ltrs from B.  

So, (5x−10)/(3x−6). Further, 16 litres is added to B.

(5x−10)/(3x−6+16)=(5x−10)/(3x+10)

this ratio now becomes 3/5. hence solving for (5x−10)(3x+10)= 3/5,

we get x= 5.

now using x=5,

we know the initial Value of A/B= 5x/3x is 25/15

Hence B is 15.

Step-by-step explanation: