Question

A bucket contains a mixture of two liquids a and b in the proportion 7:5

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively. When 9 litres of mixture are drawn off, quantity of A in mixture left:

[7x−(7/12)×9]=[7x−(21/4)]litres

Similarly quantity of B in mixture left,

[5x−(5/12)×9]=[5x−(15/4)]litres

∴ratio becomes,

[7x−(21/4)/[5x−(15/4)]=7/9

⇒(28x−21)/(20x+21)=79

⇒(252x−189)=140x+147

⇒112x=336

⇒x=3

So the can contained

7×x

=7×3

=21 litres of A initially.