A bucket full of water is revolved in a vertical circle of 2m. What should be the maximum time period of revolution so that the water does not fall at the point of maximum height ?
raveesh255:
2m is radius or diameter?
Answers
Answered by
52
let the velocity at the top of the circle be = V m/s
let Radius R = 2 meter
The centripetal force on water in the bucket should be more than the gravitational pull. Then water does not fall.
m V² / R = m g => V = √(Rg) = 2√5 m/sec as g = 10m/sec
so velocity of the bucket in the vertical circle must be minimum 2√5 m/s
then the period of revolution = T < 2πR/ V = 2.8 sec
let Radius R = 2 meter
The centripetal force on water in the bucket should be more than the gravitational pull. Then water does not fall.
m V² / R = m g => V = √(Rg) = 2√5 m/sec as g = 10m/sec
so velocity of the bucket in the vertical circle must be minimum 2√5 m/s
then the period of revolution = T < 2πR/ V = 2.8 sec
click on thansk button above pls...select best answe
Answered by
1
Answer:
How did T <2pir/v has been applied
I asked it in here because comments are not available there
Explanation:
Similar questions