a bucket is 18 cm in diameter at the top and 6 CM in diameter at the bottom if it is 8 centimetre find the capacity also find the area of sheet used in making the bucket
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Answered by
14
Answer:GIVEN :
Diameter of upper end of bucket =30cm
Radius of the upper end of the frustum of cone( r1) = 15cm
Diameter of lower end of bucket = 10 cm
radius of the lower end of the frustum of cone( r2) = 5 cm
H of the frustum of Cone = 24 cm
Slant height of bucket ( L)= √(h² + (r1- r2)²
L =√24² + (15 - 5)² = √576 + 10²
L =√(576+(100)= √676 = 26cm
L = 26 cm
Area of metal sheet require to make it = π(r1 + r2)L + πr1²
= 3.14(15 + 5) × 26 + π(5)²
= 3.14 × 20 × 26 + 25 × 3.14
= 3.14 (520+ 25)
= 545 × 3.14
= 1711.3 cm²
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Step-by-step explanation:
Answered by
39
Here,
R = 9 cm
r = 3 cm
h = 8 cm
Capacity of the bucket
=
8 (92 + 32 + 93 )
= 312cm3
Area of the metallic sheet used in making the bucket
= Curved surface area of frustum +r2
=[ℓ (R + r)] +r2
=
= 120+ 9= 129cm2
R = 9 cm
r = 3 cm
h = 8 cm
Capacity of the bucket
=
8 (92 + 32 + 93 )
= 312cm3
Area of the metallic sheet used in making the bucket
= Curved surface area of frustum +r2
=[ℓ (R + r)] +r2
=
= 120+ 9= 129cm2
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