Physics, asked by rovisharma, 6 months ago

A bucket is filled with water upto a height of 36 cm. How much a coin lying at its bottom appears to be raised when viewed from outside the water? [Refractive index of water = 4/3]​

Answers

Answered by Shaizakincsem
5

To find: How much a coin lying at its bottom appears to be raised when viewed from outside the water?

Step-by-step-explanation:

Formula used:

Refractive index: \frac{D_{real} }{D_{apparent} }

here

Refractive index of water: 4/3

Real depth = 36 cm

Apparent depth =?

Put the values

\frac{4}{3}=\frac{36}{D_{apparent} }

Cross multiply to find apparent depth to find the coin depth

D_{apparent} =\frac{36x3}{4}

D_{apparent} =27cm

The coin raised up = Real depth-Apparent depth

=36-27

= 9 cm

Final answer:

The coin seems to be raised 9 cm up from the bottom when viewed from the outside.

#SPJ2

Similar questions