Question

A bucket is filled with water upto a height of 36 cm. How much a coin lying at its bottom appears to be raised when viewed from outside the water? [Refractive index of water = 4/3]​

Answer 1

Step-by-step-Explanation:

Given: A bucket is filled with water upto s height of 36 cm. How much a coin lying at its bottom appears to raised when viewed from outside the water?[Refractive index of water 4/3]

To find: How much a coin lying at its bottom appears to raised when viewed from outside the water?

Solution:

Formula used:

$\bold{\pink{Refractive \: index = \frac{D_{real}}{D_{apparent}}}}$

here

Refractive index of water: 4/3

Real depth = 36 cm

Apparent depth =?

Put the values

$\frac{4}{3} = \frac{36}{D_{apparent}}$

Cross multiply to find apparent depth to find the coin depth

$D_{apparent} = \frac{36 \times 3}{4} \\ \\ D_{apparent} = 27 \: cm$

The coin raised up = Real depth-Apparent depth

=36-27

= 9 cm

Final answer:

The coin seems to be raised 9 cm up from bottom when viewed from outside.

Hope it helps you.

To learn more on brainly:

1)A fish at the bottom of a pond appears to be 1.2 m from the water surface. What is the depth

of the pond?

(a) 1.67 (b...

https://brainly.in/question/40937888

Answer 2

Answer:

Real Depth=36cm

Apparent Depth=?

Refractive index (n)=4/3

Formula=Apparent depth= Real depth/refractive index

AP=36÷4/3

AP=36*3÷4

AP=27

IMAGE SHIFT=REAL-APPARENT

36-27=9

It is your required answer

mark me the brainliest