Question

A bucket is filled with water upto s height of 36 cm. How much a coin lying at its bottom appears to raised when viewed from outside the water?[Refractive index of water 4/3]​

Answer 1

Step-by-step-Explanation:

Given: A bucket is filled with water upto s height of 36 cm. How much a coin lying at its bottom appears to raised when viewed from outside the water?[Refractive index of water 4/3]

To find: How much a coin lying at its bottom appears to raised when viewed from outside the water?

Solution:

Formula used:

$\bold{Refractive \: index = \frac{D_{real}}{D_{apparent}}}$

here

Refractive index of water: 4/3

Real depth = 36 cm

Apparent depth =?

Put the values

$\frac{4}{3} = \frac{36}{D_{apparent}}$

Cross multiply to find apparent depth to find the coin depth

$D_{apparent} = \frac{36 \times 3}{4} \\ \\ D_{apparent} = 27 \: cm$

The coin raised up = Real depth-Apparent depth

=36-27

= 9 cm

Final answer:

The coin seems to be raised 9 cm up from bottom when viewed from outside.

Hope it helps you.

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