Math, asked by sanjaykumarkuma4634, 1 year ago

A bucket is in form of a frustum of a cone of height is 30 cm with radii of its lower and
upper ends as 10 cm and 20 cm respectively. Find the capacity of the bucket. Also find the cost of
milk which can completely fill the container, at the rate of Rs. 25 per litre.
(Take 'TT=3.14).

Answers

Answered by kashyap20031
5
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Answered by mysticd
0

 \underline { \blue { Dimensions \:of \:a \:Frustum (Bucket) }}

 Radius \:of \: lower \:base (r) = 10 \:cm

 Radius \:of \: upper \:base (R) = 20 \:cm

 Height (h) = 30 \:cm

 Capacity \:of \:the \: bucket \\= Volume \:of \:the \: frustum \\= \frac{1}{3} \pi h ( r^{2} + rR + R^{2} ) \\= \frac{1}{3} \times 3.14 \times 30 ( 10^{2} + 10 \times 20 + 20^{2} ) \\= 3.14 \times 10 ( 100 + 200 + 400) \\= 31.4 \times 700 \\= 21980 \:cm^{3} \\= 21980 \: litres

 Cost \: of\: 1 \: litre \:milk  = Rs \:25

 Cost \: of\: 21980 \: litre \:milk = 25 \times 21980 \\= Rs \:549500

Therefore.,

 \red { Capacity \:of \:the \:container } \green { = 21980 \: litres }

 \red { Cost \: of \: milk \: in \:the \:container }\\\green { = Rs \:549500}

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