Question

A bucket is in form of frustum of a cone holds 28.490 L of water .The radii of top and bottom are 28cm and 21cm respectively.. Find height?

Answer 1

Hlooo dear....!!!/

Here,
The volume = 28.49cm
Radius r1 = 28 cm
Radius r2 = 21 cm

so volume of the frustum =
1/3 πh [r1²+r2²+r1 x r2]
so...
1/3 x 22/7 x h [28²+21²+28x21]
28490=5698/3x h
h = 15

hope it helps

@sonu

Answer 2

Hi Friend ✋✋

Your answer is :-

Volume = 28.49 L

r1 = 28 cm

r2 = 21 cm

h = ?

Volume of Frustum = 1/3 × π × h × ( r1² + r2² + ( r1 × r2 ) )

28.490/1000 m³ = 1/3 × 22/7 × h × ( 28² + 21² + ( 28 × 21 ) )

28490cm³ = 1/3 × 22/7 × h × ( 784 + 441 + 588 )

28490 = 22/21 × 1813 × h

28490 = 5698/3 × h

h = 28490 × 3 / 5698

h = 15cm

hope it helps